Your Astronomy Olympiad guide

Angular size and radians

An object's physical size tells you how wide it is. Its angular size tells you how wide it looks from your position. A small nearby object can cover the same angle as a large distant object.

8 minute lesson · Mathematics · Original foundation material

Before you start: Ratios; Powers of ten; Degrees and circles.

An object's physical size tells you how wide it is. Its angular size tells you how wide it looks from your position. A small nearby object can cover the same angle as a large distant object.

Angular diameter: lines from an observer to the top and bottom of an object of diameter D at distance dθdistance dDobserverSmall angle: θ ≈ D / d (radians)

Start with a radian

An angle in radians equals arc length divided by circle radius: θ = s/r. A complete circle has arc length 2πr, so 360° = 2π radians and 180° = π radians.

To convert degrees to radians, multiply by π/180. To convert radians to degrees, multiply by 180/π. One degree contains 60 arcminutes, and one arcminute contains 60 arcseconds.

Use the small-angle rule

For a distant object of transverse width D at distance d, its small angular width is approximately θ = D/d, with θ in radians. D and d must use the same length unit. The approximation improves as D/d becomes smaller.

For a flat object centred perpendicular to the line of sight, the exact angle is 2 arctan(D/(2d)). The simpler ratio works because a narrow viewing triangle has almost the same small-angle behaviour as a short circular arc.

A worked example

A distant object is 900 km wide and 300,000 km away. Estimate its angular width in radians and degrees.

  1. Both lengths are in kilometres, so their ratio needs no unit conversion.
  2. Use the small-angle formula: θ ≈ 900/300,000 = 0.003 radians.
  3. Convert to degrees: 0.003 × 180/π ≈ 0.1719°.
  4. Round sensibly: the object is about 0.172° wide, or 10.3 arcminutes.

0.003 radians, approximately 0.172°

A common trap: The ratio D/d gives radians, not degrees. Avoid mixing a size in metres with a distance in kilometres.

Check your understanding

If the same small object moves three times farther away, what happens to its angular width?

Show the explanation

It becomes approximately one-third as large because θ ≈ D/d and D has stayed fixed.